Question

Use the table to answer the question.

6th-Grade Average Total of Students
100–90 32
89–80 65
79–70 27
What is the part-to-part ratio for the 6th-grade averages of 100–90 to 89–80 written using a colon?

(1 point)
$$
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Answer 1

To find the part-to-part ratio for the 6th-grade averages of 100–90 to 89–80, we compare the total number of students in each range.

From the table:
- The total number of students in the 100–90 range is 32.
- The total number of students in the 89–80 range is 65.

The part-to-part ratio of 100–90 to 89–80 is therefore:

\[
32 : 65
\]

So, the part-to-part ratio for the 6th-grade averages of 100–90 to 89–80 written using a colon is:

\[
32 : 65
\]