To determine which table shows the same ratio of the number of lemons to the number of ounces of sugar, we first need to find the ratio from Liana's table.
From Liana's table:
- For 4 lemons, there are 6 ounces of sugar, so the ratio is \( \frac{4}{6} = \frac{2}{3} \).
- For 8 lemons, there are 12 ounces of sugar, so the ratio is \( \frac{8}{12} = \frac{2}{3} \).
- For 12 lemons, there are 18 ounces of sugar, so the ratio is \( \frac{12}{18} = \frac{2}{3} \).
- For 16 lemons, there are 24 ounces of sugar, so the ratio is \( \frac{16}{24} = \frac{2}{3} \).
The ratio of the number of lemons to the number of ounces of sugar is consistently \( \frac{2}{3} \).
Now let's look at the options provided:
**A.**
- 2 lemons : 3 ounces (ratio = \( \frac{2}{3} \))
- 9 lemons : 12 ounces (ratio = \( \frac{9}{12} = \frac{3}{4} \))
- 15 lemons : 18 ounces (ratio = \( \frac{15}{18} = \frac{5}{6} \))
- 18 lemons : 24 ounces (ratio = \( \frac{18}{24} = \frac{3}{4} \))
Not all ratios are \( \frac{2}{3} \).
**B.**
- 2 lemons : 3 ounces (ratio = \( \frac{2}{3} \))
- 6 lemons : 9 ounces (ratio = \( \frac{6}{9} = \frac{2}{3} \))
- 10 lemons : 15 ounces (ratio = \( \frac{10}{15} = \frac{2}{3} \))
- 14 lemons : 21 ounces (ratio = \( \frac{14}{21} = \frac{2}{3} \))
All ratios are \( \frac{2}{3} \), so this table works.
**C.**
- 3 lemons : 4 ounces (ratio = \( \frac{3}{4} \))
- 6 lemons : 8 ounces (ratio = \( \frac{6}{8} = \frac{3}{4} \))
- 9 lemons : 12 ounces (ratio = \( \frac{9}{12} = \frac{3}{4} \))
- 12 lemons : 16 ounces (ratio = \( \frac{12}{16} = \frac{3}{4} \))
Not all ratios are \( \frac{2}{3} \).
**D.**
- 5 lemons : 7 ounces (ratio = \( \frac{5}{7} \))
- 9 lemons : 13 ounces (ratio = \( \frac{9}{13} \))
- 13 lemons : 19 ounces (ratio = \( \frac{13}{19} \))
- 17 lemons : 25 ounces (ratio = \( \frac{17}{25} \))
Not all ratios are \( \frac{2}{3} \).
Only option **B** maintains the ratio of \( \frac{2}{3} \) across all entries. Thus, the answer is:
**B.**