To add \(2\sqrt{8} + 3\sqrt{8}\), you can combine the terms since they are like terms.
First, recall that: \[ \sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2} \]
Now substitute this back into the expression: \[ 2\sqrt{8} = 2(2\sqrt{2}) = 4\sqrt{2} \] \[ 3\sqrt{8} = 3(2\sqrt{2}) = 6\sqrt{2} \]
Now, add the two terms: \[ 4\sqrt{2} + 6\sqrt{2} = (4 + 6)\sqrt{2} = 10\sqrt{2} \]
Thus, the final result is: \[ 2\sqrt{8} + 3\sqrt{8} = 10\sqrt{2} \]