Let r, s, and t be the real roots of

(x - \sqrt[3]{13})(x - \sqrt[3]{53})(x - \sqrt[3]{103}) = 0.
Compute r^3 + s^3 + t^3.

1 answer

To find the value of \( r^3 + s^3 + t^3 \) where \( r, s, t \) are the real roots of the equation

\[ (x - \sqrt[3]{13})(x - \sqrt[3]{53})(x - \sqrt[3]{103}) = 0, \]

we first identify the roots. The roots are given directly as:

\[ r = \sqrt[3]{13}, \quad s = \sqrt[3]{53}, \quad t = \sqrt[3]{103}. \]

We can compute \( r^3, s^3, \) and \( t^3 \) as follows:

\[ r^3 = 13, \quad s^3 = 53, \quad t^3 = 103. \]

Now we calculate \( r^3 + s^3 + t^3 \):

\[ r^3 + s^3 + t^3 = 13 + 53 + 103. \]

We perform the addition:

\[ 13 + 53 = 66, \] \[ 66 + 103 = 169. \]

Thus, we have:

\[ r^3 + s^3 + t^3 = 169. \]

Therefore, the value of \( r^3 + s^3 + t^3 \) is

\[ \boxed{169}. \]