Question

The following data refer to a single-acting hydraulic press:
2
Area of plunger = 0,09 ml
Stroke of plunger = 0,13 m
Force applied to plunger = 300 N Area of ram = 0,45 m
4
Ignore any losses, and calculate:
(a) The volume of liquid displaced by the plunger in 6 strokes.

Answer 1

To calculate the volume of liquid displaced by the plunger in a single stroke, we can use the formula for the volume of a cylinder:

\[
\text{Volume} = \text{Area} \times \text{Stroke}
\]

Given the data:

- Area of the plunger (\( A_p \)) = 0.09 m²
- Stroke of the plunger (\( S \)) = 0.13 m

Now, calculate the volume displaced in one stroke:

\[
\text{Volume displaced in one stroke} = A_p \times S = 0.09 \, \text{m}^2 \times 0.13 \, \text{m}
\]

\[
= 0.0117 \, \text{m}^3
\]

Now, to find the volume displaced in 6 strokes:

\[
\text{Volume displaced in 6 strokes} = 6 \times \text{Volume displaced in one stroke}
\]

\[
= 6 \times 0.0117 \, \text{m}^3 = 0.0702 \, \text{m}^3
\]

So, the volume of liquid displaced by the plunger in 6 strokes is:

\[
\text{Volume displaced} = 0.0702 \, \text{m}^3
\]