Asked by Alice
What would be the product of a reaction between methanal and pyrrolidine in acid?
I know that normally a reaction between a carbonyl and a secondary amine would form an enamine. Here I am confused because there are no hydrogens that can be removed to form the enamine as this is methanal. I'm guessing that the nitrogen will attack the C=O double bond and then water will be formed as a leaving group, the nitrogen lone pair will come down to form a double bond and push this off. I'm not sure where to go from here as there will be a positive charge on the N.
I know that normally a reaction between a carbonyl and a secondary amine would form an enamine. Here I am confused because there are no hydrogens that can be removed to form the enamine as this is methanal. I'm guessing that the nitrogen will attack the C=O double bond and then water will be formed as a leaving group, the nitrogen lone pair will come down to form a double bond and push this off. I'm not sure where to go from here as there will be a positive charge on the N.
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.