To determine which of the given equations is balanced, we need to count the number of each type of atom on both sides of the equation.
Let's analyze each option:
A. C3H8 + 11 O2 → 3 CO2 + 8 H2O
- On the left:
- C: 3 (from C3H8)
- H: 8 (from C3H8)
- O: 22 (from 11 O2)
- On the right:
- C: 3 (from 3 CO2)
- H: 16 (from 8 H2O)
- O: 22 (from 3 CO2 + 8 H2O)
- The total counts:
- C: 3, H: 8 left vs. C: 3, H: 16 right (not balanced)
B. C3H8 + 3 O2 → CO2 + H2O
- On the left:
- C: 3 (from C3H8)
- H: 8 (from C3H8)
- O: 6 (from 3 O2)
- On the right:
- C: 1 (from CO2)
- H: 2 (from H2O)
- O: 3 (from CO2 + H2O)
- The total counts:
- C: 3, H: 8 left vs. C: 1, H: 2 right (not balanced)
C. C3H8 + 5 O2 → 3 CO2 + 4 H2O
- On the left:
- C: 3 (from C3H8)
- H: 8 (from C3H8)
- O: 10 (from 5 O2)
- On the right:
- C: 3 (from 3 CO2)
- H: 8 (from 4 H2O)
- O: 10 (from 3 CO2 + 4 H2O)
- The total counts:
- C: 3, H: 8, O: 10 left vs. C: 3, H: 8, O: 10 right (balanced)
D. 2 C3H8 + 4 O2 → 2 CO2 + 4 H2O
- On the left:
- C: 6 (from 2 C3H8)
- H: 16 (from 2 C3H8)
- O: 8 (from 4 O2)
- On the right:
- C: 2 (from 2 CO2)
- H: 8 (from 4 H2O)
- O: 8 (from 2 CO2 + 4 H2O)
- The total counts:
- C: 6, H: 16 left vs. C: 2, H: 8 right (not balanced)
The only balanced equation from the options provided is:
C. C3H8 + 5 O2 → 3 CO2 + 4 H2O
5 answers