Question

The width of a wheelchair-accessible parking space is 60% of its length. What is the area of the parking space if the width is 9 feet?

Answer 1

To find the area of the wheelchair-accessible parking space, we first need to determine its length based on the information that the width is 60% of its length.

Let \( L \) be the length of the parking space. According to the problem, we have:

\[
\text{Width} = 0.6L
\]

We are given that the width is 9 feet. Therefore, we can set up the equation:

\[
0.6L = 9
\]

To find \( L \), we divide both sides of the equation by 0.6:

\[
L = \frac{9}{0.6}
\]

Calculating this gives:

\[
L = 15 \text{ feet}
\]

Now that we have both the width and length of the parking space, we can find the area. The area \( A \) of a rectangle is given by the formula:

\[
A = \text{Width} \times \text{Length}
\]

Substituting in the values we have:

\[
A = 9 \text{ feet} \times 15 \text{ feet}
\]

Calculating this, we find:

\[
A = 135 \text{ square feet}
\]

Thus, the area of the wheelchair-accessible parking space is

\[
\boxed{135} \text{ square feet}.
\]