Prescription A has an Initial value of 674 mg/L and a half-life 9 hours. Which equation will help us determine the remaining level after 1 day?

y=674(1/2)^1/9

y = 674(1/2)^24/9

y=674(1/2)^9/24

y = 674(1/2)^9/1

1 answer

To determine the remaining level of a substance after a certain period of time, you can use the formula for exponential decay based on the concept of half-life. The amount remaining after time \( t \) can be modeled by the equation:

\[ y = y_0 \left( \frac{1}{2} \right)^{\frac{t}{\text{half-life}}} \]

Where:

  • \( y_0 \) is the initial amount (674 mg/L in this case),
  • \( t \) is the total time elapsed,
  • and the half-life is the time it takes for the substance to reduce to half its initial value (9 hours).

For a time of 1 day, we first need to convert days to hours. Since 1 day = 24 hours, we will use \( t = 24 \) hours.

Now, we plug these values into our formula:

\[ y = 674 \left( \frac{1}{2} \right)^{\frac{24}{9}} \]

Thus, the equation that best helps to determine the remaining level after 1 day is:

\[ y = 674 \left( \frac{1}{2} \right)^{\frac{24}{9}} \]

So the correct choice from the options provided is:

y = 674(1/2)^(24/9)

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