To solve for \( f \) in the equation
\[ \frac{f}{-12} = 30, \]
you can start by multiplying both sides by -12:
\[ f = 30 \times (-12). \]
Calculating the right side:
\[ f = -360. \]
Thus,
\[ f = -360. \]
f/–12
= 30
f =
11 answers
Solve for t.
–29t = –261
t =
–29t = –261
t =
To solve for \( t \) in the equation
\[ -29t = -261, \]
you can start by dividing both sides by -29:
\[ t = \frac{-261}{-29}. \]
Since the negatives cancel out, this simplifies to:
\[ t = \frac{261}{29}. \]
Dividing 261 by 29 gives:
\[ t = 9. \]
Therefore,
\[ t = 9. \]
Solve for q.
–15q = –420
q =
–15q = –420
q =
To solve for \( q \) in the equation
\[ -15q = -420, \]
you can start by dividing both sides by -15:
\[ q = \frac{-420}{-15}. \]
Since the negatives cancel out, this simplifies to:
\[ q = \frac{420}{15}. \]
Now, dividing 420 by 15 gives:
\[ q = 28. \]
Therefore,
\[ q = 28. \]
Solve for s.
s/5 = –21
s =
s/5 = –21
s =
To solve for \( s \) in the equation
\[ \frac{s}{5} = -21, \]
you can start by multiplying both sides by 5:
\[ s = -21 \times 5. \]
Calculating the right side gives:
\[ s = -105. \]
Therefore,
\[ s = -105. \]
Solve for v.
179 = v + –52
v =
179 = v + –52
v =
To solve for \( v \) in the equation
\[ 179 = v - 52, \]
you can add 52 to both sides:
\[ 179 + 52 = v. \]
Calculating the left side gives:
\[ v = 231. \]
Therefore,
\[ v = 231. \]
Solve for f.
924 = f + 96
f =
924 = f + 96
f =
To solve for \( f \) in the equation
\[ 924 = f + 96, \]
you can subtract 96 from both sides:
\[ 924 - 96 = f. \]
Calculating the left side gives:
\[ f = 828. \]
Therefore,
\[ f = 828. \]