Asked by mada
(3+4i)(3-4i)
Answers
Answered by
Reiny
just expand it as if the i was a variable
(3+4i)(3-4i)
= 9 - 12i + 12i -12i^2, now remember i^2 = -1
= 9 - 12(-1)
= 9+12
= 21
(3+4i)(3-4i)
= 9 - 12i + 12i -12i^2, now remember i^2 = -1
= 9 - 12(-1)
= 9+12
= 21
Answered by
mada
wait when you factor it wouldnt it be 9-12i+12i-16i^2
Answered by
Reiny
of course, my silly error
Answered by
mada
its totally cool you have helped alot :)
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