To find the perfect squares of the numbers 5 through 9, we can calculate each square as follows:
- \(5^2 = 25\)
- \(6^2 = 36\)
- \(7^2 = 49\)
- \(8^2 = 64\)
- \(9^2 = 81\)
Now we can fill in the table:
| Numbers | Squares | |---------|----------| | 5 | 25 | | 6 | 36 | | 7 | 49 | | 8 | 64 | | 9 | 81 |
Since \(45\) is between \(36\) (which is \(6^2\)) and \(49\) (which is \(7^2\)), we can conclude that:
\[ 6 < \sqrt{45} < 7 \]
To approximate \(\sqrt{45}\), we can use the fact that it is closer to \(6\) than to \(7\).