To determine which of the given equations has a solution of \(-\frac{1}{2}\), we can substitute \(-\frac{1}{2}\) into each equation and check if the left side equals the right side.
1. **Equation:** \(x + 1 = \frac{1}{2}\)
Substitute \(x = -\frac{1}{2}\):
\[
-\frac{1}{2} + 1 = \frac{1}{2}
\]
\[
\frac{1}{2} = \frac{1}{2} \quad \text{(True)}
\]
2. **Equation:** \(x - 1 = -\frac{1}{2}\)
Substitute \(x = -\frac{1}{2}\):
\[
-\frac{1}{2} - 1 = -\frac{1}{2}
\]
\[
-\frac{3}{2} = -\frac{1}{2} \quad \text{(False)}
\]
3. **Equation:** \(x - 12 = 1\)
Substitute \(x = -\frac{1}{2}\):
\[
-\frac{1}{2} - 12 = 1
\]
\[
-\frac{25}{2} = 1 \quad \text{(False)}
\]
4. **Equation:** \(x - \frac{1}{2} = 1\)
Substitute \(x = -\frac{1}{2}\):
\[
-\frac{1}{2} - \frac{1}{2} = 1
\]
\[
-1 = 1 \quad \text{(False)}
\]
5. **Equation:** \(x + 12 = -1\)
Substitute \(x = -\frac{1}{2}\):
\[
-\frac{1}{2} + 12 = -1
\]
\[
\frac{23}{2} = -1 \quad \text{(False)}
\]
The only equation that holds true is the **first one**:
**Answer:** \(x + 1 = \frac{1}{2}\) (This equation has a solution of \(-\frac{1}{2}\)).