Question
A car with a mass of 1200kg accelerates from rest to 20m/s in 5 seconds. What is the net force acting on the car?
Answers
GPT-4o mini
To find the net force acting on the car, we can use Newton's second law of motion, which states that the net force \( F \) is equal to the mass \( m \) of an object multiplied by its acceleration \( a \):
\[
F = m \cdot a
\]
First, we need to calculate the acceleration of the car. We can use the following formula for acceleration \( a \):
\[
a = \frac{\Delta v}{\Delta t}
\]
where:
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the time taken for that change.
The car accelerates from rest (initial velocity \( u = 0 \) m/s) to a final velocity \( v = 20 \) m/s in \( \Delta t = 5 \) seconds.
Substituting the values into the acceleration formula:
\[
a = \frac{v - u}{\Delta t} = \frac{20 \, \text{m/s} - 0 \, \text{m/s}}{5 \, \text{s}} = \frac{20 \, \text{m/s}}{5 \, \text{s}} = 4 \, \text{m/s}^2
\]
Now that we have the acceleration, we can find the net force:
\[
F = m \cdot a = 1200 \, \text{kg} \cdot 4 \, \text{m/s}^2 = 4800 \, \text{N}
\]
Therefore, the net force acting on the car is **4800 N**.
\[
F = m \cdot a
\]
First, we need to calculate the acceleration of the car. We can use the following formula for acceleration \( a \):
\[
a = \frac{\Delta v}{\Delta t}
\]
where:
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the time taken for that change.
The car accelerates from rest (initial velocity \( u = 0 \) m/s) to a final velocity \( v = 20 \) m/s in \( \Delta t = 5 \) seconds.
Substituting the values into the acceleration formula:
\[
a = \frac{v - u}{\Delta t} = \frac{20 \, \text{m/s} - 0 \, \text{m/s}}{5 \, \text{s}} = \frac{20 \, \text{m/s}}{5 \, \text{s}} = 4 \, \text{m/s}^2
\]
Now that we have the acceleration, we can find the net force:
\[
F = m \cdot a = 1200 \, \text{kg} \cdot 4 \, \text{m/s}^2 = 4800 \, \text{N}
\]
Therefore, the net force acting on the car is **4800 N**.