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solve the following quadratic equation using square roots. round to the nearest hundredth if necessary: (x-6)^2 = 51Asked by Smartypants
                Solve the following quadratic equation using square roots. Round to the nearest hundredth if necessary: (x−6)^2=51.(1 point)
            
            
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                    Answered by
            GPT-4o mini
            
    To solve the quadratic equation \((x - 6)^2 = 51\), we can use the square root method. Here are the steps:
1. Take the square root of both sides of the equation:
\[
x - 6 = \pm \sqrt{51}
\]
2. Calculate \(\sqrt{51}\):
\[
\sqrt{51} \approx 7.14 \quad (\text{rounded to two decimal places})
\]
3. Now, we have two equations to solve:
\[
x - 6 = 7.14 \quad \text{and} \quad x - 6 = -7.14
\]
4. Solve the first equation:
\[
x = 7.14 + 6
\]
\[
x \approx 13.14
\]
5. Solve the second equation:
\[
x = -7.14 + 6
\]
\[
x \approx -1.14
\]
Thus, the solutions to the equation \((x - 6)^2 = 51\) are:
\[
x \approx 13.14 \quad \text{and} \quad x \approx -1.14
\]
    
1. Take the square root of both sides of the equation:
\[
x - 6 = \pm \sqrt{51}
\]
2. Calculate \(\sqrt{51}\):
\[
\sqrt{51} \approx 7.14 \quad (\text{rounded to two decimal places})
\]
3. Now, we have two equations to solve:
\[
x - 6 = 7.14 \quad \text{and} \quad x - 6 = -7.14
\]
4. Solve the first equation:
\[
x = 7.14 + 6
\]
\[
x \approx 13.14
\]
5. Solve the second equation:
\[
x = -7.14 + 6
\]
\[
x \approx -1.14
\]
Thus, the solutions to the equation \((x - 6)^2 = 51\) are:
\[
x \approx 13.14 \quad \text{and} \quad x \approx -1.14
\]
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