Question

120 % of Year 1 population = Year 2 population
1.2 · x = 36

The increase in foxes from Year 1 to Year 2

The population of foxes in Year 2

The population of

Answer 1

To find the population of foxes in Year 1 (denoted as \(x\)), we can start from the equation you provided:

\[1.2 \cdot x = 36\]

To solve for \(x\), divide both sides by 1.2:

\[
x = \frac{36}{1.2}
\]

Calculating this, we find:

\[
x = 30
\]

So, the population of foxes in Year 1 is 30.

Next, to find the increase in foxes from Year 1 to Year 2, we subtract the Year 1 population from the Year 2 population:

\[
\text{Increase} = \text{Year 2 population} - \text{Year 1 population} = 36 - 30 = 6
\]

The population of foxes in Year 2 is already stated in the equation as 36.

In summary:
- The population of foxes in Year 1: **30**
- The increase in foxes from Year 1 to Year 2: **6**
- The population of foxes in Year 2: **36**