Asked by wish I was Indoraptor
Find the volume of the cylinder, in cubic centimeters. Use 3.14 for pi. Round your answer to the nearest tenth.
h(5 cm) r(3 cm)
h(5 cm) r(3 cm)
Answers
Answered by
wish I was Indoraptor
Find the volume of the cylinder, in cubic meters. Use 3.14 for pi. Round your answer to the nearest hundredth
the cylinder is slanted off to the side
h=7 slant hight=10 r=4
the cylinder is slanted off to the side
h=7 slant hight=10 r=4
Answered by
wish I was Indoraptor
Find the volume of the cylinder, in cubic meters. Use 3.14 for pi. Round your answer to the nearest hundredth
h=7 r=4
h=7 r=4
Answered by
wish I was Indoraptor
A can of peas has a height of 6 inches and a radius of 3 inches. What is the volume, in cubic inches, of the can? Use 3.14 for p
Answered by
wish I was Indoraptor
A gas tank has a height of 8 feet and a width of 6 feet. What is the volume, in cubic feet, of the gas tank? Use 3.14 for pi
Answered by
GPT-4o mini
To find the volume of a cylinder, you can use the formula:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
Given:
- \( r = 3 \, \text{cm} \)
- \( h = 5 \, \text{cm} \)
- Use \( \pi \approx 3.14 \)
Now, plug in the values:
\[
V = 3.14 \times (3^2) \times 5
\]
First, calculate \( 3^2 \):
\[
3^2 = 9
\]
Now, substitute that back into the volume formula:
\[
V = 3.14 \times 9 \times 5
\]
Next, calculate \( 9 \times 5 \):
\[
9 \times 5 = 45
\]
Now, substitute that value:
\[
V = 3.14 \times 45
\]
Next, calculate \( 3.14 \times 45 \):
\[
V = 141.3
\]
Thus, the volume of the cylinder is approximately \( 141.3 \) cubic centimeters. Since the answer is already rounded to the nearest tenth, the final result is:
\[
\boxed{141.3} \, \text{cm}^3
\]
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
Given:
- \( r = 3 \, \text{cm} \)
- \( h = 5 \, \text{cm} \)
- Use \( \pi \approx 3.14 \)
Now, plug in the values:
\[
V = 3.14 \times (3^2) \times 5
\]
First, calculate \( 3^2 \):
\[
3^2 = 9
\]
Now, substitute that back into the volume formula:
\[
V = 3.14 \times 9 \times 5
\]
Next, calculate \( 9 \times 5 \):
\[
9 \times 5 = 45
\]
Now, substitute that value:
\[
V = 3.14 \times 45
\]
Next, calculate \( 3.14 \times 45 \):
\[
V = 141.3
\]
Thus, the volume of the cylinder is approximately \( 141.3 \) cubic centimeters. Since the answer is already rounded to the nearest tenth, the final result is:
\[
\boxed{141.3} \, \text{cm}^3
\]
Answered by
GPT-4o mini
To find the volume of a cylinder, whether it is vertical or slanted, we still use the formula for the volume of a cylinder:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height of the cylinder (the vertical height).
In this case, you provided the following dimensions:
- \( r = 4 \, \text{m} \) (the radius)
- \( h = 7 \, \text{m} \) (the vertical height of the cylinder)
We will use the value \( \pi \approx 3.14 \).
Now, plug in the values into the volume formula:
\[
V = 3.14 \times (4^2) \times 7
\]
First, calculate \( 4^2 \):
\[
4^2 = 16
\]
Now, substitute that back into the volume formula:
\[
V = 3.14 \times 16 \times 7
\]
Next, calculate \( 16 \times 7 \):
\[
16 \times 7 = 112
\]
Now, substitute that value:
\[
V = 3.14 \times 112
\]
Next, calculate \( 3.14 \times 112 \):
\[
V = 350.68
\]
So, the volume of the cylinder is approximately \( 350.68 \) cubic meters. Rounded to the nearest hundredth, the final result is:
\[
\boxed{350.68} \, \text{m}^3
\]
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height of the cylinder (the vertical height).
In this case, you provided the following dimensions:
- \( r = 4 \, \text{m} \) (the radius)
- \( h = 7 \, \text{m} \) (the vertical height of the cylinder)
We will use the value \( \pi \approx 3.14 \).
Now, plug in the values into the volume formula:
\[
V = 3.14 \times (4^2) \times 7
\]
First, calculate \( 4^2 \):
\[
4^2 = 16
\]
Now, substitute that back into the volume formula:
\[
V = 3.14 \times 16 \times 7
\]
Next, calculate \( 16 \times 7 \):
\[
16 \times 7 = 112
\]
Now, substitute that value:
\[
V = 3.14 \times 112
\]
Next, calculate \( 3.14 \times 112 \):
\[
V = 350.68
\]
So, the volume of the cylinder is approximately \( 350.68 \) cubic meters. Rounded to the nearest hundredth, the final result is:
\[
\boxed{350.68} \, \text{m}^3
\]
Answered by
GPT-4o mini
To find the volume of the cylinder, you can use the formula:
\[
V = \pi r^2 h
\]
given:
- \( h = 7 \, \text{m} \) (the height),
- \( r = 4 \, \text{m} \) (the radius),
- Use \( \pi \approx 3.14 \).
Now, plug the values into the volume formula:
\[
V = 3.14 \times (4^2) \times 7
\]
First, calculate \( 4^2 \):
\[
4^2 = 16
\]
Now substitute that back into the formula:
\[
V = 3.14 \times 16 \times 7
\]
Next, calculate \( 16 \times 7 \):
\[
16 \times 7 = 112
\]
Now substitute that value back into the equation:
\[
V = 3.14 \times 112
\]
Finally, calculate \( 3.14 \times 112 \):
\[
V = 350.68
\]
Thus, the volume of the cylinder is approximately \( 350.68 \) cubic meters. Rounded to the nearest hundredth, the final result is:
\[
\boxed{350.68} \, \text{m}^3
\]
\[
V = \pi r^2 h
\]
given:
- \( h = 7 \, \text{m} \) (the height),
- \( r = 4 \, \text{m} \) (the radius),
- Use \( \pi \approx 3.14 \).
Now, plug the values into the volume formula:
\[
V = 3.14 \times (4^2) \times 7
\]
First, calculate \( 4^2 \):
\[
4^2 = 16
\]
Now substitute that back into the formula:
\[
V = 3.14 \times 16 \times 7
\]
Next, calculate \( 16 \times 7 \):
\[
16 \times 7 = 112
\]
Now substitute that value back into the equation:
\[
V = 3.14 \times 112
\]
Finally, calculate \( 3.14 \times 112 \):
\[
V = 350.68
\]
Thus, the volume of the cylinder is approximately \( 350.68 \) cubic meters. Rounded to the nearest hundredth, the final result is:
\[
\boxed{350.68} \, \text{m}^3
\]
Answered by
GPT-4o mini
To find the volume of a cylinder, you use the formula:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
For the can of peas:
- Height \( h = 6 \) inches
- Radius \( r = 3 \) inches
- Use \( \pi \approx 3.14 \)
Now, plug in the values:
\[
V = 3.14 \times (3^2) \times 6
\]
First, calculate \( 3^2 \):
\[
3^2 = 9
\]
Next, substitute that value back into the formula:
\[
V = 3.14 \times 9 \times 6
\]
Now, calculate \( 9 \times 6 \):
\[
9 \times 6 = 54
\]
Substitute that back into the volume equation:
\[
V = 3.14 \times 54
\]
Finally, calculate \( 3.14 \times 54 \):
\[
V = 169.56
\]
Thus, the volume of the can is approximately \( 169.56 \) cubic inches. Therefore, the final answer is:
\[
\boxed{169.56} \, \text{cubic inches}
\]
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
For the can of peas:
- Height \( h = 6 \) inches
- Radius \( r = 3 \) inches
- Use \( \pi \approx 3.14 \)
Now, plug in the values:
\[
V = 3.14 \times (3^2) \times 6
\]
First, calculate \( 3^2 \):
\[
3^2 = 9
\]
Next, substitute that value back into the formula:
\[
V = 3.14 \times 9 \times 6
\]
Now, calculate \( 9 \times 6 \):
\[
9 \times 6 = 54
\]
Substitute that back into the volume equation:
\[
V = 3.14 \times 54
\]
Finally, calculate \( 3.14 \times 54 \):
\[
V = 169.56
\]
Thus, the volume of the can is approximately \( 169.56 \) cubic inches. Therefore, the final answer is:
\[
\boxed{169.56} \, \text{cubic inches}
\]
Answered by
GPT-4o mini
To find the volume of a gas tank that is cylindrical in shape, you can use the formula for the volume of a cylinder:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
Given:
- Height \( h = 8 \) feet
- Width (diameter) = 6 feet
First, we need to find the radius. The radius \( r \) is half of the width (diameter):
\[
r = \frac{6}{2} = 3 \, \text{feet}
\]
Now, substitute the values into the volume formula:
\[
V = 3.14 \times (3^2) \times 8
\]
First, calculate \( 3^2 \):
\[
3^2 = 9
\]
Now substitute that back into the volume formula:
\[
V = 3.14 \times 9 \times 8
\]
Next, calculate \( 9 \times 8 \):
\[
9 \times 8 = 72
\]
Now substitute that back into the equation:
\[
V = 3.14 \times 72
\]
Finally, calculate \( 3.14 \times 72 \):
\[
V = 226.08
\]
Thus, the volume of the gas tank is approximately \( 226.08 \) cubic feet. Therefore, the final answer is:
\[
\boxed{226.08} \, \text{cubic feet}
\]
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( r \) is the radius, and
- \( h \) is the height.
Given:
- Height \( h = 8 \) feet
- Width (diameter) = 6 feet
First, we need to find the radius. The radius \( r \) is half of the width (diameter):
\[
r = \frac{6}{2} = 3 \, \text{feet}
\]
Now, substitute the values into the volume formula:
\[
V = 3.14 \times (3^2) \times 8
\]
First, calculate \( 3^2 \):
\[
3^2 = 9
\]
Now substitute that back into the volume formula:
\[
V = 3.14 \times 9 \times 8
\]
Next, calculate \( 9 \times 8 \):
\[
9 \times 8 = 72
\]
Now substitute that back into the equation:
\[
V = 3.14 \times 72
\]
Finally, calculate \( 3.14 \times 72 \):
\[
V = 226.08
\]
Thus, the volume of the gas tank is approximately \( 226.08 \) cubic feet. Therefore, the final answer is:
\[
\boxed{226.08} \, \text{cubic feet}
\]