Question

How many solutions would the equation x2=−9 have? You do not need to solve for x.(1 point)
The equation would have
solution(s).

Answer 1

thats wrong

Answer 2

The equation \( x^2 = -9 \) has no real solutions because the square of a real number cannot be negative. However, if we consider complex numbers, the equation would have 2 imaginary solutions.

So, the final answer is:
The equation would have **2 solution(s)**.

Answer 3

I apologize for any confusion. Let's clarify the scenario:

The equation \( x^2 = -9 \) can be analyzed as follows:

1. **Real Solutions:** In the real number system, there are no real solutions since the square of a real number cannot equal a negative number.

2. **Complex Solutions:** If we extend our consideration to complex numbers, the equation can be rewritten as:
\[
x^2 = -9 \implies x = \pm i\sqrt{9} \implies x = \pm 3i
\]
Thus, there are 2 complex solutions.

So, to clarify:
- **Real solutions:** 0
- **Complex solutions:** 2

Depending on the context of the question (if you're asking for real solutions or all solutions), you might say:
- **0 real solutions**
- **2 complex solutions**

If your question pertains to only the real number system, then it would indeed have **0 solutions** and I mistakenly noted the complex solutions without specifying the context. Thank you for your patience.