To determine the constant term of the quadratic function in standard form, we need to first clarify the information provided. A quadratic function in standard form can be written as:
\[ f(x) = ax^2 + bx + c \]
where \(c\) represents the constant term.
From your statement, it appears that the graph is U-shaped (which typically indicates a quadratic function opening upwards), and you mentioned “on 1, -3”. Assuming that this point (1, -3) is the vertex of the parabola, we can derive the function.
The vertex form of a quadratic function is given by:
\[ f(x) = a(x - h)^2 + k \]
where \((h, k)\) is the vertex of the parabola. In your case, the vertex appears to be at the point (1, -3). Thus, \(h = 1\) and \(k = -3\). The equation becomes:
\[ f(x) = a(x - 1)^2 - 3 \]
To find the constant term \(c\), we need to find the value of the function when \(x = 0\) (the y-intercept):
\[ f(0) = a(0 - 1)^2 - 3 = a(1) - 3 = a - 3 \]
Without additional information, we cannot determine the exact value of \(a\). However, the constant term \(c\) (f(0)) will be \(a - 3\).
If you meant something different by "on 1, -3" (like it being a point on the graph other than the vertex), please clarify, and I can help more accurately!