Question
Between which two consecutive whole numbers does the length of the diagonal fall?
Which whole number is it closer to? Use the drop-down menus to show your answer. If one side is \sqrt{18}
Which whole number is it closer to? Use the drop-down menus to show your answer. If one side is \sqrt{18}
Answers
GPT-4o mini
To determine the length of the diagonal and between which two consecutive whole numbers it falls, we can apply the Pythagorean theorem.
Given that one side is \(\sqrt{18}\), we can assume the other side is also \(\sqrt{18}\) (in a right triangle scenario, since the question does not specify otherwise).
The formula to calculate the diagonal \(d\) (hypotenuse) when both sides are equal is:
\[
d = \sqrt{a^2 + b^2}
\]
Substituting \(a = \sqrt{18}\) and \(b = \sqrt{18}\):
\[
d = \sqrt{(\sqrt{18})^2 + (\sqrt{18})^2}
\]
\[
d = \sqrt{18 + 18}
\]
\[
d = \sqrt{36}
\]
\[
d = 6
\]
Now we can analyze the solution. The diagonal \(d\) is exactly \(6\), which is a whole number itself.
Thus, it falls between the consecutive whole numbers \(5\) and \(6\) and is closer to \(6\).
**Final Answers:**
- The diagonal falls between: **5 and 6**
- It is closer to: **6**
Given that one side is \(\sqrt{18}\), we can assume the other side is also \(\sqrt{18}\) (in a right triangle scenario, since the question does not specify otherwise).
The formula to calculate the diagonal \(d\) (hypotenuse) when both sides are equal is:
\[
d = \sqrt{a^2 + b^2}
\]
Substituting \(a = \sqrt{18}\) and \(b = \sqrt{18}\):
\[
d = \sqrt{(\sqrt{18})^2 + (\sqrt{18})^2}
\]
\[
d = \sqrt{18 + 18}
\]
\[
d = \sqrt{36}
\]
\[
d = 6
\]
Now we can analyze the solution. The diagonal \(d\) is exactly \(6\), which is a whole number itself.
Thus, it falls between the consecutive whole numbers \(5\) and \(6\) and is closer to \(6\).
**Final Answers:**
- The diagonal falls between: **5 and 6**
- It is closer to: **6**