An experimental egg farm is raising chickens to produce low cholesterol eggs. A lab tested 12 randomly selected eggs and found that the mean amount of cholesterol was x = 186 mg. The sample standard deviation was found to be s = 19.0 mg on this group. Assume that the population is normally distributed.
Question: Find the margin of error for a 95% confidence interval. Round your answer to the nearest tenths.
Answer: 1.96(19/√16) = 9.31
Question: Find a 95% confidence interval for the mean µ cholesterol content for all experimental eggs. Assume that the population is normally distributed.
Answer:
1.96 – 9.31 = 7.35
1.96 + 9.31 = 11.27
Question: Find the margin of error for a 95% confidence interval. Round your answer to the nearest tenths.
Answer: 1.96(19/√16) = 9.31
Question: Find a 95% confidence interval for the mean µ cholesterol content for all experimental eggs. Assume that the population is normally distributed.
Answer:
1.96 – 9.31 = 7.35
1.96 + 9.31 = 11.27
Answers
Answered by
PsyDAG
Why is it the "√16" when n - 1 = 11?
Standard error of the mean = Standard deviation/√(n-1)
95% confidence interval = mean ± 1.96 SE. Why are you not using mean = 186?
Standard error of the mean = Standard deviation/√(n-1)
95% confidence interval = mean ± 1.96 SE. Why are you not using mean = 186?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.