To find the equation of the trend line in slope-intercept form (y = mx + b), we need to determine the slope (m) and the y-intercept (b) based on the points given.
From the points you provided:
- (0, 30) is the y-intercept, so b = 30.
- The slope (m) can be calculated using the formula: \[ m = \frac{\Delta y}{\Delta x} \]
We can use two of the points to calculate the slope. Let's use the points (0, 30) and (30, 50):
- \(\Delta y = 50 - 30 = 20\)
- \(\Delta x = 30 - 0 = 30\)
Now, calculate the slope:
\[ m = \frac{20}{30} = \frac{2}{3} \]
Now that we have both the slope and the y-intercept:
- m = \(\frac{2}{3}\)
- b = 30
Thus, the equation of the trend line is:
\[ y = \frac{2}{3}x + 30 \]
This gives us the answer:
y = \(\frac{2}{3}\)x + 30