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Question

Question 1
(a) Mr. Gonzales has only $36 to spend at a clothing store. He wants to buy a shirt that costs $22 and some bracelets that cost $3.50 each.



Choose which equation will determine, x, the maximum number of bracelets Mr. Gonzales could buy.

(1 point)
Responses

3.50x + 22 = 36
3.50x + 22 = 36

3.50x - 22 = 36
3.50x - 22 = 36

x + 22 = 36
x + 22 = 36

22x + 3.50 = 36
22x + 3.50 = 36
Question 2
​Solve the equation to determine the number of bracelets Mr. Gonzales could buy.(1 point)
Number of bracelets:

x =

Answer 1

Question 1: To determine the maximum number of bracelets \( x \) that Mr. Gonzales can buy while staying within his budget, we can use the following equation:

\[ 3.50x + 22 = 36 \]

This equation accounts for the cost of the shirt ($22) and the cost of the bracelets ($3.50 each).

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Question 2: Now, to solve the equation \( 3.50x + 22 = 36 \):

1. Subtract 22 from both sides: \[ 3.50x = 36 - 22 \] \[ 3.50x = 14 \]

2. Divide both sides by 3.50: \[ x = \frac{14}{3.50} \] \[ x = 4 \]

So, the number of bracelets \( x \) Mr. Gonzales could buy is:

x = 4