Question
The density of silver is 10.49 g/cm3
10.49
g
/
cm
3
. If a sample of silver has a volume of 0.2 m3
0.2
m
3
, what is the mass of the sample?
10.49
g
/
cm
3
. If a sample of silver has a volume of 0.2 m3
0.2
m
3
, what is the mass of the sample?
Answers
GPT-4o mini
To calculate the mass of the silver sample, we can use the formula:
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
First, we need to ensure that the units of density and volume are compatible. The density of silver is given as \(10.49 \, \text{g/cm}^3\), and the volume of the sample is given as \(0.2 \, \text{m}^3\).
1. **Convert the volume from cubic meters to cubic centimeters**:
Since \(1 \, \text{m}^3 = 1,000,000 \, \text{cm}^3\) (or \(1 \, \text{m}^3 = 10^6 \, \text{cm}^3\)), we convert:
\[
0.2 \, \text{m}^3 = 0.2 \times 1,000,000 \, \text{cm}^3 = 200,000 \, \text{cm}^3
\]
2. **Calculate the mass using the density**:
Now, we can use the density to find the mass:
\[
\text{Mass} = 10.49 \, \text{g/cm}^3 \times 200,000 \, \text{cm}^3
\]
Calculating this gives:
\[
\text{Mass} = 10.49 \times 200,000 = 2,098,000 \, \text{g}
\]
3. **Convert the mass to kilograms** (since \(1 \, \text{kg} = 1000 \, \text{g}\)):
\[
\text{Mass} = \frac{2,098,000 \, \text{g}}{1000} = 2098 \, \text{kg}
\]
Thus, the mass of the silver sample is **2098 kg**.
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
First, we need to ensure that the units of density and volume are compatible. The density of silver is given as \(10.49 \, \text{g/cm}^3\), and the volume of the sample is given as \(0.2 \, \text{m}^3\).
1. **Convert the volume from cubic meters to cubic centimeters**:
Since \(1 \, \text{m}^3 = 1,000,000 \, \text{cm}^3\) (or \(1 \, \text{m}^3 = 10^6 \, \text{cm}^3\)), we convert:
\[
0.2 \, \text{m}^3 = 0.2 \times 1,000,000 \, \text{cm}^3 = 200,000 \, \text{cm}^3
\]
2. **Calculate the mass using the density**:
Now, we can use the density to find the mass:
\[
\text{Mass} = 10.49 \, \text{g/cm}^3 \times 200,000 \, \text{cm}^3
\]
Calculating this gives:
\[
\text{Mass} = 10.49 \times 200,000 = 2,098,000 \, \text{g}
\]
3. **Convert the mass to kilograms** (since \(1 \, \text{kg} = 1000 \, \text{g}\)):
\[
\text{Mass} = \frac{2,098,000 \, \text{g}}{1000} = 2098 \, \text{kg}
\]
Thus, the mass of the silver sample is **2098 kg**.