What is the value of y?

b4c−7=by/c7

1 answer

To solve for \( y \) in the equation

\[ b^4c - 7 = \frac{by}{c} \cdot 7, \]

we can first simplify the right side of the equation:

\[ b^4c - 7 = \frac{7by}{c}. \]

Next, we can multiply both sides by \( c \) to eliminate the fraction:

\[ c(b^4c - 7) = 7by. \]

This simplifies to:

\[ cb^4c - 7c = 7by. \]

Now, we want to isolate \( y \). We can divide both sides by \( 7b \) (assuming \( b \neq 0 \)):

\[ y = \frac{cb^4c - 7c}{7b}. \]

This can be simplified further:

\[ y = \frac{c(b^4c - 7)}{7b}. \]

So, the final expression for \( y \) is:

\[ y = \frac{c(b^4c - 7)}{7b}. \]