Jerrod found the length of the hypotenuse of a right triangle with legs that are 3 ft and 1 ft. Is his answer correct?c2=32+12c2=9+1c2=8c=8–√(1 point)ResponsesNo, he subtracted 1 and 9 instead of adding.No, he subtracted 1 and 9 instead of adding.No, he set up the Pythagorean theorem incorrectly.No, he set up the Pythagorean theorem incorrectly.Yes, he correctly calculated the length of the hypotenuse.Yes, he correctly calculated the length of the hypotenuse.No, he made an error finding the square root.

To determine if Jerrod's answer is correct, we need to check his setup of the Pythagorean theorem and his calculations.

The Pythagorean theorem states that in a right triangle:

\[ c^2 = a^2 + b^2 \]

where \( c \) is the length of the hypotenuse, and \( a \) and \( b \) are the lengths of the two legs of the triangle.

In this case, the legs \( a \) and \( b \) are 3 ft and 1 ft. According to the theorem:

\[ c^2 = 3^2 + 1^2 \]
\[ c^2 = 9 + 1 \]
\[ c^2 = 10 \]

Next, to find \( c \), we take the square root of both sides:

\[ c = \sqrt{10} \]

Jerrod wrote:

\[ c^2 = 3^2 + 1^2 \]
\[ c^2 = 9 + 1 \]
\[ c^2 = 8 \]
\[ c = \sqrt{8} \]

Here, he made a mistake in the addition. The sum of \( 9 + 1 \) is \( 10 \), not \( 8 \).

So the correct calculations show that:

- The correct setup is \( c^2 = 3^2 + 1^2 \).
- The correct result is \( c^2 = 10 \) and \( c = \sqrt{10} \).

Jerrod's answer is therefore incorrect because he set up the Pythagorean theorem incorrectly by computing \( 9 + 1 \) as \( 8 \).

The correct response is: "No, he set up the Pythagorean theorem incorrectly."