Okay, let's break it down in a way that a 7th grader might explain it!
So, there is this cool pattern for placing pennies on a chessboard. Each square on the board gets a certain number of pennies depending on its number. Here's how it works:
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For square 1, the number of pennies is: \[ 2^{(1-1)} = 2^0 = 1 \text{ penny} \]
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For square 2, the number of pennies is: \[ 2^{(2-1)} = 2^1 = 2 \text{ pennies} \]
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For square 3, the number of pennies is: \[ 2^{(3-1)} = 2^2 = 4 \text{ pennies} \]
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For square 4, the number of pennies is: \[ 2^{(4-1)} = 2^3 = 8 \text{ pennies} \]
And it keeps going like that! Basically, for each square number \( n \), you have \( 2^{(n-1)} \) pennies.
Now, let’s figure out how many pennies are on square 14. We do this by plugging 14 into our formula:
\[ \text{Number of pennies on square 14} = 2^{(14-1)} = 2^{13} \]
Now we need to calculate \( 2^{13} \).
Here's how \( 2^{13} \) works:
- It means you multiply 2 by itself 13 times, or: \[ 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \]
And when you do that, you get: \[ 2^{13} = 8192 \]
So, on the 14th square, there are 8192 pennies!
So the answer is: \[ \boxed{8192} \]