Asked by Garrett
find the equation (in standard form using only integers) for the line through (2, -5) that is parallel to
2x-3y=5
2x-3y=5
Answers
Answered by
Reiny
simplest way ...
since the new line is parallel to the old line, its equation must differ only in the constant, so ..
new line:
2x - 3y = c
plug in point (2,-5)
4 + 15 = c = 19
2x - 3y = 19 , all done!
since the new line is parallel to the old line, its equation must differ only in the constant, so ..
new line:
2x - 3y = c
plug in point (2,-5)
4 + 15 = c = 19
2x - 3y = 19 , all done!
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