Question

Black fur(B) in guinea pigs is dominant over white fur(b).
Find the probability of a white offspring in a cross: Bb x bb.(1 point)
Responses

0%
0%

25%
25%

50%
50%

75%
75%

100%

Answer 1

To determine the probability of a white offspring in the cross Bb (heterozygous black fur) x bb (homozygous white fur), we can set up a simple Punnett square.

- The alleles for the black-furred guinea pig (Bb) are B and b.
- The alleles for the white-furred guinea pig (bb) are b and b.

When we set up the Punnett square, we will have:

```
b b
__________
B | Bb Bb
b | bb bb
```

From the Punnett square, we can see the following genotypes of the offspring:

- 2 Bb (black fur)
- 2 bb (white fur)

This gives us a total of 4 offspring genotypes:
- 2 out of 4 (or 50%) will have the genotype bb (white fur).

Therefore, the probability of having a white offspring from this cross Bb x bb is **50%**.