Question

Use the table to answer the question.

x
f(x)
g(x)

-2 -1 -1
-1 34
0
0 1 1
1 114
2
2 3 3


(1 point)
Compare the functions f(x)
and g(x)

When is f(x)
greater than g(x)
?

f(x)
is greater than g(x)
when
< x <

Answer 1

To compare the functions \( f(x) \) and \( g(x) \) based on the provided values, we can fill in the missing values for both functions using the table given.

Here are the known values:

| \( x \) | \( f(x) \) | \( g(x) \) |
|---------|-------------|-------------|
| -2 | -1 | -1 |
| -1 | 34 | 0 |
| 0 | 1 | 1 |
| 1 | 114 | 0 |
| 2 | 3 | 3 |

Now we need to determine when \( f(x) \) is greater than \( g(x) \).

1. For \( x = -2 \):
- \( f(-2) = -1 \)
- \( g(-2) = -1 \)
- \( f(-2) \) is not greater than \( g(-2) \).

2. For \( x = -1 \):
- \( f(-1) = 34 \)
- \( g(-1) = 0 \)
- \( f(-1) > g(-1) \).

3. For \( x = 0 \):
- \( f(0) = 1 \)
- \( g(0) = 1 \)
- \( f(0) \) is not greater than \( g(0) \).

4. For \( x = 1 \):
- \( f(1) = 114 \)
- \( g(1) = 0 \)
- \( f(1) > g(1) \).

5. For \( x = 2 \):
- \( f(2) = 3 \)
- \( g(2) = 3 \)
- \( f(2) \) is not greater than \( g(2) \).

From this analysis, we can conclude:
- \( f(x) \) is greater than \( g(x) \) for the interval \( -1 < x < 1 \).

So the final answer is:

**f(x) is greater than g(x) when \( -1 < x < 1 \).**