The line below has a slope of $\frac{2}{5}.$ Find the $x$-intercept.

The line passes through (0,0).

1 answer

To find the \( x \)-intercept of a line, we use the information that the line passes through the origin \((0, 0)\) and has a slope of \(\frac{2}{5}\).

The equation of a line can be expressed in the slope-intercept form:

\[ y = mx + b \]

where \( m \) is the slope and \( b \) is the \( y \)-intercept. Since the line passes through the origin, the \( y \)-intercept \( b = 0\). Therefore, the equation of the line simplifies to:

\[ y = \frac{2}{5}x \]

Next, to find the \( x \)-intercept, we set \( y = 0 \) and solve for \( x \):

\[ 0 = \frac{2}{5}x \]

To isolate \( x \), we multiply both sides by \(\frac{5}{2}\):

\[ 0 \cdot \frac{5}{2} = x \quad \Rightarrow \quad x = 0 \]

Thus, the \( x \)-intercept of the line is

\[ \boxed{0} \]

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