Question
Use the chemical equation to answer the question.
2H (g) + O (g) → 2H O(l)
Which statement describes the breaking and forming of bonds in the reaction?
(1 point)
2 2 2
The reaction requires breaking four O–H bonds, and then forming one O=O bond and two H–H bonds.
The reaction requires breaking four O–H bonds, and then forming one H–H bond and two O=O bonds.
The reaction requires breaking one H–H bond and two O=O bonds, and then forming four O–H bonds.
The reaction requires breaking one O=O bond and two H-H bonds, and then forming four O–H bonds.
2H (g) + O (g) → 2H O(l)
Which statement describes the breaking and forming of bonds in the reaction?
(1 point)
2 2 2
The reaction requires breaking four O–H bonds, and then forming one O=O bond and two H–H bonds.
The reaction requires breaking four O–H bonds, and then forming one H–H bond and two O=O bonds.
The reaction requires breaking one H–H bond and two O=O bonds, and then forming four O–H bonds.
The reaction requires breaking one O=O bond and two H-H bonds, and then forming four O–H bonds.
Answers
GPT-4o mini
To analyze the reaction \( 2H_2(g) + O_2(g) \rightarrow 2H_2O(l) \), we should first recognize which bonds are present in the reactants and products:
- In the reactants \( 2H_2(g) \), there are two H–H bonds (since each molecule of \( H_2 \) has one H–H bond, and we have two \( H_2 \)).
- In the reactant \( O_2(g) \), there is one O=O (double bond).
- In the products \( 2H_2O(l) \), each water molecule contains two O–H bonds, and since there are two water molecules, this results in a total of four O–H bonds.
Now, let's break down the process:
1. **Breaking bonds**:
- We break 2 H-H bonds (from 2 \( H_2 \)) and 1 O=O bond (from \( O_2 \)).
2. **Forming bonds**:
- We form 4 O–H bonds (2 from each of the 2 \( H_2O \) molecules).
Thus, during the reaction:
- Bonds broken: 2 H–H + 1 O=O = 3 total bonds broken.
- Bonds formed: 4 O–H bonds.
Now we can evaluate the statements:
1. The reaction requires breaking four O–H bonds, and then forming one O=O bond and two H–H bonds. **(Incorrect)**
2. The reaction requires breaking four O–H bonds, and then forming one H–H bond and two O=O bonds. **(Incorrect)**
3. The reaction requires breaking one H–H bond and two O=O bonds, and then forming four O–H bonds. **(Incorrect)**
4. The reaction requires breaking one O=O bond and two H–H bonds, and then forming four O–H bonds. **(Correct)**
The correct statement that describes the breaking and forming of bonds in the reaction is:
**The reaction requires breaking one O=O bond and two H–H bonds, and then forming four O–H bonds.**
- In the reactants \( 2H_2(g) \), there are two H–H bonds (since each molecule of \( H_2 \) has one H–H bond, and we have two \( H_2 \)).
- In the reactant \( O_2(g) \), there is one O=O (double bond).
- In the products \( 2H_2O(l) \), each water molecule contains two O–H bonds, and since there are two water molecules, this results in a total of four O–H bonds.
Now, let's break down the process:
1. **Breaking bonds**:
- We break 2 H-H bonds (from 2 \( H_2 \)) and 1 O=O bond (from \( O_2 \)).
2. **Forming bonds**:
- We form 4 O–H bonds (2 from each of the 2 \( H_2O \) molecules).
Thus, during the reaction:
- Bonds broken: 2 H–H + 1 O=O = 3 total bonds broken.
- Bonds formed: 4 O–H bonds.
Now we can evaluate the statements:
1. The reaction requires breaking four O–H bonds, and then forming one O=O bond and two H–H bonds. **(Incorrect)**
2. The reaction requires breaking four O–H bonds, and then forming one H–H bond and two O=O bonds. **(Incorrect)**
3. The reaction requires breaking one H–H bond and two O=O bonds, and then forming four O–H bonds. **(Incorrect)**
4. The reaction requires breaking one O=O bond and two H–H bonds, and then forming four O–H bonds. **(Correct)**
The correct statement that describes the breaking and forming of bonds in the reaction is:
**The reaction requires breaking one O=O bond and two H–H bonds, and then forming four O–H bonds.**