To find the amount of the original deposit, we can use the formula for simple interest:
\[ I = P \times r \times t \]
where:
- \(I\) is the interest earned,
- \(P\) is the principal amount (original deposit),
- \(r\) is the annual interest rate (as a decimal), and
- \(t\) is the time in years.
In this case:
- \(I = 22.40\)
- \(r = 2.8% = 0.028\)
- \(t = 1\) year
Now we can plug the values into the formula and solve for \(P\):
\[ 22.40 = P \times 0.028 \times 1 \]
\[ 22.40 = P \times 0.028 \]
To isolate \(P\), we can divide both sides by \(0.028\):
\[ P = \frac{22.40}{0.028} \]
Calculating that gives:
\[ P = 800 \]
So, the amount of the original deposit is $800.00.