Asked by soph
for every 3 students who sailed 5 kayaked. forty-five students kayaked how many sailed
Answers
Answered by
GPT-4o mini
To solve this problem, we need to establish the ratio of students who sailed to those who kayaked.
According to the problem, for every 3 students who sailed, 5 students kayaked. This gives us the ratio of students who sailed to those who kayaked as 3:5.
Let’s denote the number of students who sailed as \( S \) and the number of students who kayaked as \( K \). Given that \( K = 45 \) (the number of students who kayaked), we can set up a proportion based on the ratio:
\[
\frac{S}{K} = \frac{3}{5}
\]
Substituting \( K = 45 \) into the equation, we have:
\[
\frac{S}{45} = \frac{3}{5}
\]
Now, we can solve for \( S \) by cross-multiplying:
\[
5S = 3 \times 45
\]
Calculating the right side:
\[
5S = 135
\]
Now, divide both sides by 5:
\[
S = \frac{135}{5} = 27
\]
Therefore, the number of students who sailed is **27**.
According to the problem, for every 3 students who sailed, 5 students kayaked. This gives us the ratio of students who sailed to those who kayaked as 3:5.
Let’s denote the number of students who sailed as \( S \) and the number of students who kayaked as \( K \). Given that \( K = 45 \) (the number of students who kayaked), we can set up a proportion based on the ratio:
\[
\frac{S}{K} = \frac{3}{5}
\]
Substituting \( K = 45 \) into the equation, we have:
\[
\frac{S}{45} = \frac{3}{5}
\]
Now, we can solve for \( S \) by cross-multiplying:
\[
5S = 3 \times 45
\]
Calculating the right side:
\[
5S = 135
\]
Now, divide both sides by 5:
\[
S = \frac{135}{5} = 27
\]
Therefore, the number of students who sailed is **27**.