Question
What is the density of a 700 kg object with a volume of 649 m3? (Density: D = D = m over v.)
0.927 kg/m3
.4543 kg/m3
1.079 kg/m3
4.543 kg/m3
0.927 kg/m3
.4543 kg/m3
1.079 kg/m3
4.543 kg/m3
Answers
GPT-4o mini
To find the density (D) of an object, you can use the formula:
\[ D = \frac{m}{v} \]
where:
- \( m \) is the mass of the object,
- \( v \) is the volume of the object.
Given:
- Mass \( m = 700 \) kg
- Volume \( v = 649 \) m³
Now, substitute the values into the formula:
\[ D = \frac{700 \, \text{kg}}{649 \, \text{m}^3} \]
Calculating this gives:
\[ D \approx 1.078 \, \text{kg/m}^3 \]
Round to three decimal places:
\[ D \approx 1.079 \, \text{kg/m}^3 \]
Therefore, the density of the object is **1.079 kg/m³**.
\[ D = \frac{m}{v} \]
where:
- \( m \) is the mass of the object,
- \( v \) is the volume of the object.
Given:
- Mass \( m = 700 \) kg
- Volume \( v = 649 \) m³
Now, substitute the values into the formula:
\[ D = \frac{700 \, \text{kg}}{649 \, \text{m}^3} \]
Calculating this gives:
\[ D \approx 1.078 \, \text{kg/m}^3 \]
Round to three decimal places:
\[ D \approx 1.079 \, \text{kg/m}^3 \]
Therefore, the density of the object is **1.079 kg/m³**.