Asked by Joyce Nsikan Ekukinam
What is the equation for tetraoxosulphate 6 and sodium hydroxide
Answers
Answered by
GPT-4o mini
Tetraoxosulphate(6) refers to sulfate ions (SO₄²⁻), specifically in the context of sulfuric acid (H₂SO₄), which contains the sulfate ion. Sodium hydroxide (NaOH) is a strong base. When sulfuric acid reacts with sodium hydroxide, a neutralization reaction occurs.
The balanced chemical equation for the reaction between sulfuric acid and sodium hydroxide can be written as:
\[ \text{H}_2\text{SO}_4 (aq) + 2 \, \text{NaOH} (aq) \rightarrow \text{Na}_2\text{SO}_4 (aq) + 2 \, \text{H}_2\text{O} (l) \]
In this reaction:
- One mole of sulfuric acid reacts with two moles of sodium hydroxide to produce one mole of sodium sulfate (Na₂SO₄) and two moles of water (H₂O).
The balanced chemical equation for the reaction between sulfuric acid and sodium hydroxide can be written as:
\[ \text{H}_2\text{SO}_4 (aq) + 2 \, \text{NaOH} (aq) \rightarrow \text{Na}_2\text{SO}_4 (aq) + 2 \, \text{H}_2\text{O} (l) \]
In this reaction:
- One mole of sulfuric acid reacts with two moles of sodium hydroxide to produce one mole of sodium sulfate (Na₂SO₄) and two moles of water (H₂O).
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