A train is traveling at a velocity of 45m/s to the East. One passenger is walking on the train. What is the passengers relative velocity to the ground if they are traveling 2 m/s to the East.

Question

A
90 m/s
45 m/s
47 m/s
D) 44 m/s

Answer 1

To find the passenger's relative velocity to the ground, we need to combine the velocity of the train and the velocity of the passenger. Since both the train and the passenger are moving in the same direction (East), we simply add their velocities together.

• Velocity of the train = 45 m/s East
• Velocity of the passenger = 2 m/s East

The relative velocity of the passenger to the ground is:

\[ \text{Relative velocity} = \text{Velocity of the train} + \text{Velocity of the passenger} \]

\[ \text{Relative velocity} = 45 , \text{m/s} + 2 , \text{m/s} = 47 , \text{m/s} \]

So, the correct answer is:

47 m/s