Use the image to answer the question.

An illustration shows quadrant one of a coordinate plane where the x-axis and y-axis range from 0 to 6 in increments of 1. The y-axis is titled total cost in dollars and the x-axis is titled number of markers. A solid line, labeled A, is marked on the graph and passes through coordinates left parenthesis 0 comma 0 right parenthesis and left parenthesis 3 comma 6 right parenthesis. A dotted line, labeled B, passes through coordinates left parenthesis 0 comma 0 right parenthesis and left parenthesis 6 comma 3 right parenthesis.

Predict what the total cost would be for buying 10 of the type A markers.

(1 point)
Responses

$5.00
$5.00

$0.50
$0.50

$20.00
$20.00

$2.00
$2.00
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1 answer

To predict the total cost for buying 10 of the type A markers based on the provided graph details, we first need to understand the relationship represented by line A.

  1. Line A passes through the points (0, 0) and (3, 6). The slope of this line can be determined by the change in y divided by the change in x between these two points:

    • Slope (m) = (6 - 0) / (3 - 0) = 6 / 3 = 2.
  2. The equation of a line in slope-intercept form is given by: \[ y = mx + b \] Since the line passes through the origin (0, 0), we have \( b = 0 \). Therefore, the equation becomes: \[ y = 2x \]

  3. This means that the cost (y) for buying x markers is given by the equation: \[ \text{Total Cost} = 2 \times \text{Number of Markers} \]

  4. For 10 markers: \[ \text{Total Cost} = 2 \times 10 = 20 \]

Thus, the total cost for buying 10 of the type A markers would be $20.00.