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A segment has endpoints X(−10,0) and Y(−2,6). Consider its image after a 180° (counterclockwise) rotation about the origin. Sel...Asked by lol
A segment has endpoints X(−10,0) and Y(−2,6) . Consider its image after a 180° (counterclockwise) rotation about the origin. Select the coordinates of Y′ .(1 point)
Responses
Y′(−6,2)
upper Y prime left parenthesis negative 6 comma 2 right parenthesis
Y′(6,−2)
upper Y prime left parenthesis 6 comma negative 2 right parenthesis
Y′(2,−6)
upper Y prime left parenthesis 2 comma negative 6 right parenthesis
Y′(−2,−6)
upper Y prime left parenthesis negative 2 comma negative 6 right parenthesis
Responses
Y′(−6,2)
upper Y prime left parenthesis negative 6 comma 2 right parenthesis
Y′(6,−2)
upper Y prime left parenthesis 6 comma negative 2 right parenthesis
Y′(2,−6)
upper Y prime left parenthesis 2 comma negative 6 right parenthesis
Y′(−2,−6)
upper Y prime left parenthesis negative 2 comma negative 6 right parenthesis
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the image of point \( Y(-2, 6) \) after a \( 180^\circ \) counterclockwise rotation about the origin, we can use the following transformation rule:
For a point \( (x, y) \), the coordinates after a \( 180^\circ \) rotation about the origin will be \( (-x, -y) \).
Applying this to point \( Y(-2, 6) \):
1. Negate the x-coordinate:
\[
-(-2) = 2
\]
2. Negate the y-coordinate:
\[
-(6) = -6
\]
Thus, the coordinates of \( Y' \) after the rotation are \( (2, -6) \).
So the correct response is:
\[
Y'(2, -6)
\]
For a point \( (x, y) \), the coordinates after a \( 180^\circ \) rotation about the origin will be \( (-x, -y) \).
Applying this to point \( Y(-2, 6) \):
1. Negate the x-coordinate:
\[
-(-2) = 2
\]
2. Negate the y-coordinate:
\[
-(6) = -6
\]
Thus, the coordinates of \( Y' \) after the rotation are \( (2, -6) \).
So the correct response is:
\[
Y'(2, -6)
\]
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