To solve this problem, we need to set up equations based on the information provided.
Let's denote:
- \( x \) = the amount of Earl Grey tea (in pounds)
- \( y \) = the amount of Orange Pekoe tea (in pounds)
We know the following:
- The total weight of the new blend is 600 pounds.
- The selling price of the new blend is $2.50 per pound.
We can set up the equations:
-
The total weight equation: \[ x + y = 600 \]
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The revenue from the new blend should equal the revenue if all the tea were sold separately. The revenue from the new blend is: \[ 600 \times 2.50 = 1500 \] The revenue from Earl Grey tea is: \[ 4x \] The revenue from Orange Pekoe tea is: \[ 2y \] Therefore, we set up the revenue equation: \[ 4x + 2y = 1500 \]
Now we have a system of linear equations:
- \( x + y = 600 \)
- \( 4x + 2y = 1500 \)
Next, we can solve this system. First, we can simplify the second equation by dividing everything by 2: \[ 2x + y = 750 \] Now we have a simplified system:
- \( x + y = 600 \) (Equation 1)
- \( 2x + y = 750 \) (Equation 2)
Now, we can solve for \( y \) in terms of \( x \) from Equation 1: \[ y = 600 - x \]
Substituting this expression for \( y \) into Equation 2: \[ 2x + (600 - x) = 750 \] Now simplify: \[ 2x + 600 - x = 750 \] \[ x + 600 = 750 \] Subtracting 600 from both sides: \[ x = 150 \]
Now substituting \( x = 150 \) back into the expression for \( y \): \[ y = 600 - 150 = 450 \]
Thus, the amounts required for the blend are:
- Earl Grey tea: \( \boxed{150} \) pounds
- Orange Pekoe tea: \( \boxed{450} \) pounds
We can also confirm that the revenue aligns with expectations:
- Revenue from Earl Grey: \( 150 \times 4 = 600 \) dollars
- Revenue from Orange Pekoe: \( 450 \times 2 = 900 \) dollars
- Total Revenue: \( 600 + 900 = 1500 \) dollars
This confirms our solution is correct.