3/8(-8-3y)

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1 answer

To expand the expression \( \frac{3}{8}(-8 - 3y) \), follow these steps:

  1. Distribute \( \frac{3}{8} \) to both terms inside the parentheses:

\[ \frac{3}{8} \cdot (-8) + \frac{3}{8} \cdot (-3y) \]

  1. Calculate each term separately:
  • For the first term: \[ \frac{3}{8} \cdot (-8) = -3 \]

  • For the second term: \[ \frac{3}{8} \cdot (-3y) = -\frac{9}{8}y \]

  1. Combine the results:

\[ -3 - \frac{9}{8}y \]

So, the expanded form of \( \frac{3}{8}(-8 - 3y) \) is:

\[ -3 - \frac{9}{8}y \]