To solve the quadratic equation \((x + 12)^2 = 9\) using square roots, follow these steps:
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Take the square root of both sides: \[ \sqrt{(x + 12)^2} = \sqrt{9} \] This gives you: \[ x + 12 = 3 \quad \text{or} \quad x + 12 = -3 \]
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Solve the equations:
- From \(x + 12 = 3\): \[ x = 3 - 12 \Rightarrow x = -9 \]
- From \(x + 12 = -3\): \[ x = -3 - 12 \Rightarrow x = -15 \]
Thus, the solutions are \(x = -9\) and \(x = -15\).
The answer is: \[ {-9, -15} \]
So the correct response is: \({−9,−15}\) left brace negative 9 comma negative 15 right brace.