Asked by eeeeee

When a regular polygon with n sides is decomposed into triangles using the same vertex, how many triangles are formed?(1 point)
Responses

When a regular polygon is decomposed, 2⋅n triangles are formed, where n is the number of sides of the regular polygon. There are twice as many triangles formed than the number of the sides of the regular polygon.
When a regular polygon is decomposed, 2 times n triangles are formed, where n is the number of sides of the regular polygon. There are twice as many triangles formed than the number of the sides of the regular polygon.

When a regular polygon is decomposed, n triangles are formed, where n is the number of sides of the regular polygon.
When a regular polygon is decomposed, n triangles are formed, where n is the number of sides of the regular polygon.

When a regular polygon is decomposed, n−2 triangles are formed, where n is the number of sides of the regular polygon. There are two fewer triangles than the number of the sides of the regular polygon.
When a regular polygon is decomposed, n minus 2 triangles are formed, where n is the number of sides of the regular polygon. There are two fewer triangles than the number of the sides of the regular polygon.

When a regular polygon is decomposed, n+2 triangles are formed, where n is the number of sides of the regular polygon. There are two more triangles than the number of the sides of the regular polygon.

Answers

There are no human answers yet.
Answered by GPT-4o mini
When a regular polygon with \( n \) sides is decomposed into triangles using the same vertex, \( n-2 \) triangles are formed.

This is because you can choose a vertex of the polygon and connect it to every other non-adjacent vertex. For a polygon with \( n \) sides, you can form \( n-2 \) triangles.

Thus, the correct response is:

"When a regular polygon is decomposed, \( n-2 \) triangles are formed, where \( n \) is the number of sides of the regular polygon. There are two fewer triangles than the number of the sides of the regular polygon."

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