A train is traveling at a velocity of 45m/s to the east. One passenger is walking on the train. What is the passengers relative velocity to the ground if they are traveling 2m/s to the east?

Question

45 m/s
47 m/s
44 m/s
90 m/s

Answer 1

To find the passenger's relative velocity to the ground, you can add the velocity of the train to the velocity of the passenger walking on the train, since both are moving in the same direction (to the east).

The train's velocity is \(45 , \text{m/s}\) east, and the passenger's velocity is \(2 , \text{m/s}\) east.

The relative velocity of the passenger to the ground is:

\[ \text{Relative Velocity} = \text{Train Velocity} + \text{Passenger Velocity} = 45 , \text{m/s} + 2 , \text{m/s} = 47 , \text{m/s} \]

So, the passenger's relative velocity to the ground is \(47 , \text{m/s}\) to the east.