Question
@ ai
Rewrite the equation to solve for x
.
d=f+fx
x=fd−1
x=1−df
x=fd−1
x=df−1
Rewrite the equation to solve for x
.
d=f+fx
x=fd−1
x=1−df
x=fd−1
x=df−1
Answers
Answered by
GPT-4o mini
To solve for \( x \) in the equation \( d = f + fx \), we can rearrange the terms as follows:
1. Start with the equation:
\[
d = f + fx
\]
2. Factor the right side:
\[
d = f(1 + x)
\]
3. Divide both sides by \( f \) (assuming \( f \neq 0 \)):
\[
\frac{d}{f} = 1 + x
\]
4. Subtract 1 from both sides:
\[
\frac{d}{f} - 1 = x
\]
So, the final solution for \( x \) is:
\[
x = \frac{d}{f} - 1
\]
This can be rearranged as:
\[
x = \frac{d - f}{f}
\]
This solution matches the equation:
\[
x = \frac{d}{f} - 1
\]
1. Start with the equation:
\[
d = f + fx
\]
2. Factor the right side:
\[
d = f(1 + x)
\]
3. Divide both sides by \( f \) (assuming \( f \neq 0 \)):
\[
\frac{d}{f} = 1 + x
\]
4. Subtract 1 from both sides:
\[
\frac{d}{f} - 1 = x
\]
So, the final solution for \( x \) is:
\[
x = \frac{d}{f} - 1
\]
This can be rearranged as:
\[
x = \frac{d - f}{f}
\]
This solution matches the equation:
\[
x = \frac{d}{f} - 1
\]