To solve the system of equations using the substitution method, we start with the two equations given:
- \( y = -2x + 1 \) (Equation 1)
- \( -4x = -2y + 10 \) (Equation 2)
Now, we can substitute Equation 1 into Equation 2.
Step 1: Substitute \( y \) in Equation 2
From Equation 1, we know that:
\[ y = -2x + 1 \]
Now, substitute \( y \) in Equation 2:
\[ -4x = -2(-2x + 1) + 10 \]
Step 2: Simplify the equation
Now, simplify the right side:
\[ -4x = -2(-2x) - 2(1) + 10 \] \[ -4x = 4x - 2 + 10 \] \[ -4x = 4x + 8 \]
Step 3: Solve for \( x \)
Now, add \( 4x \) to both sides:
\[ -4x + 4x = 4x + 8 + 4x \] \[ 0 = 8x + 8 \]
Now, subtract 8 from both sides:
\[ -8 = 8x \]
Now, divide by 8:
\[ x = -1 \]
Step 4: Substitute \( x \) back to find \( y \)
Now that we have \( x = -1 \), we can substitute this back into Equation 1 to find \( y \):
\[ y = -2(-1) + 1 \] \[ y = 2 + 1 \] \[ y = 3 \]
Final Solution
So, the solution to the system of equations is:
\[ \boxed{(-1, 3)} \]