Question
Find midpoint M of the line segment with endpoints J(1.2,3.4) and K(4.8,−2.3) . If the solution includes a decimal, do not round.
(1 point)
The midpoint M of segment JK¯¯¯¯¯¯¯¯ is at (
,
).
(1 point)
The midpoint M of segment JK¯¯¯¯¯¯¯¯ is at (
,
).
Answers
GPT-4o mini
To find the midpoint \( M \) of the line segment with endpoints \( J(1.2, 3.4) \) and \( K(4.8, -2.3) \), you can use the midpoint formula:
\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
where \( (x_1, y_1) \) are the coordinates of point \( J \) and \( (x_2, y_2) \) are the coordinates of point \( K \).
Substituting in the coordinates of \( J \) and \( K \):
\[
M = \left( \frac{1.2 + 4.8}{2}, \frac{3.4 + (-2.3)}{2} \right)
\]
Calculating the x-coordinate:
\[
x = \frac{1.2 + 4.8}{2} = \frac{6.0}{2} = 3.0
\]
Calculating the y-coordinate:
\[
y = \frac{3.4 - 2.3}{2} = \frac{1.1}{2} = 0.55
\]
Therefore, the midpoint \( M \) is at:
\[
M(3.0, 0.55)
\]
So, the final answer is:
The midpoint \( M \) of segment \( JK \) is at \( (3.0, 0.55) \).
\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
where \( (x_1, y_1) \) are the coordinates of point \( J \) and \( (x_2, y_2) \) are the coordinates of point \( K \).
Substituting in the coordinates of \( J \) and \( K \):
\[
M = \left( \frac{1.2 + 4.8}{2}, \frac{3.4 + (-2.3)}{2} \right)
\]
Calculating the x-coordinate:
\[
x = \frac{1.2 + 4.8}{2} = \frac{6.0}{2} = 3.0
\]
Calculating the y-coordinate:
\[
y = \frac{3.4 - 2.3}{2} = \frac{1.1}{2} = 0.55
\]
Therefore, the midpoint \( M \) is at:
\[
M(3.0, 0.55)
\]
So, the final answer is:
The midpoint \( M \) of segment \( JK \) is at \( (3.0, 0.55) \).