Question

4x+y=-5
20x+5y=10

Answer 1

To solve the system of equations:

1. \( 4x + y = -5 \)
2. \( 20x + 5y = 10 \)

We can start by simplifying the second equation. Notice that the second equation can be simplified by dividing every term by 5:

\[
20x + 5y = 10 \implies 4x + y = 2
\]

Now we have the simplified system:

1. \( 4x + y = -5 \)
2. \( 4x + y = 2 \)

If we subtract the first equation from the second:

\[
(4x + y) - (4x + y) = 2 - (-5)
\]

This results in:

\[
0 = 7
\]

This is a contradiction, which means that the system of equations has no solution. The two lines represented by these equations are parallel and do not intersect.