The length of JK is square root 61

The length of LK is 5
And is he length of side JL is 6
The perimeter off triangle JKL in simplest tadical form is
11
Square root 25+Square root 36
11+Square root61
11+Square root 25+Square root 36

1 answer

To find the perimeter of triangle JKL, we simply add the lengths of all three sides:

  1. \( JK = \sqrt{61} \)
  2. \( LK = 5 \)
  3. \( JL = 6 \)

Now, we can add these lengths together:

\[ \text{Perimeter} = JK + LK + JL = \sqrt{61} + 5 + 6 \]

Combining the lengths gives:

\[ \text{Perimeter} = \sqrt{61} + 11 \]

This represents the perimeter of triangle JKL in simplest radical form:

\[ \text{Perimeter} = 11 + \sqrt{61} \]

Among the options you provided, the correct answer is:

11 + \sqrt{61}.