Use the image to answer the question.

To determine whether the given points are solutions to the system of equations \( y = 2x + 2 \) and \( y = 2x - 4 \), we will substitute the x-coordinates of each point into both equations and check if the corresponding y-values match.

1. **Point (0, -4):**
- For the first equation \( y = 2x + 2 \):
- Substitute \( x = 0 \):
\[
y = 2(0) + 2 = 2
\]
- The y-value is 2, which does not match -4.
- For the second equation \( y = 2x - 4 \):
- Substitute \( x = 0 \):
\[
y = 2(0) - 4 = -4
\]
- The y-value is -4, which matches. Thus, (0, -4) is a solution to the second equation but not to the first.

2. **Point (0, 2):**
- For the first equation \( y = 2x + 2 \):
- Substitute \( x = 0 \):
\[
y = 2(0) + 2 = 2
\]
- The y-value is 2, which matches 2.
- For the second equation \( y = 2x - 4 \):
- Substitute \( x = 0 \):
\[
y = 2(0) - 4 = -4
\]
- The y-value is -4, which does not match 2. Thus, (0, 2) is a solution to the first equation but not to the second.

Since neither of the points (0, -4) nor (0, 2) satisfies both equations simultaneously, the answer is:

**Neither of these points are solutions.**